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Starting Scheme

First we start up Scheme. If we're using RScheme under UNIX, that's probably by typing rs at the UNIX % prompt. (RScheme might be installed under a different name on your system, perhaps rscheme, if so, use that name instead. If you're not using UNIX, start up RScheme the way you start up any program on your system, perhaps by clicking on its icon. If you're using UNIX but your shell has a different prompt, like >, don't worry about it.

[ Note to my (UT CS)students: on our machines, RScheme is installed as /p/bin/runscheme. You can just type that at the UNIX prompt, or if you have /p/bin in your path, plain runscheme will do. ]

%rs

Now the Scheme system starts up and prints out some information about itself, usually including including the name and version version number, and then gives you a Scheme prompt. We'll pretend that the prompt is Scheme>, but on your system it's probably something different. (For RScheme, it's something like top[0]=>, where the first few characters give you some information about the state of the system, and the => tells you it's ready for input.)

Scheme then waits for you to type in an expression and hit <RETURN>. (By that I mean hit the "RETURN" or "ENTER" key on the keyboard. In some Scheme systems, these may be distinct keys, and you may have to hit "ENTER"; the documentation for your system will tell you which key does what.)

Scheme lets you type, echoing the characters to the screen, and doesn't do anything else until you hit <RETURN>. Until you hit <RETURN>, you can back up to correct typing mistakes (just as you can in an operating system's command shell), using the delete or backspace key.

Now type in a variable definition (define myvar 10), and hit <RETURN>. What's happening on the screen looks something like this.

Generational Real-Time Garbage Collector Version 0.5
RScheme version 0.7
Scheme>(define myvar 10)
#void
Scheme>

Here we defined a variable named myvar, giving it the initial value 10. Scheme read what we typed and figured out what it meant, and then allocated some storage for the variable binding, and initialized that storage with (a pointer to) 10. Scheme keeps track of the fact that the storage it allocated is now known as myvar, as well as keeping track of the value in it.

What Scheme prints out after evaluating this expression may be different on your system (you may not see #void). That's because the Scheme standard doesn't specify what's returned as the value of a definition expression. (It's possible that your Scheme system will print out something a little more verbose, or different, or nothing at all as the value of a define expression. Don't worry about it.)

You don't usually use the result value of a definition--you're just defining something to use later. Depending on the implementation you're using, you'll see whatever the implementors chose to have definitions return. In some systems, a special unusable value is returned, and Scheme will suppress the printing of these meaningless values to avoid clutter on the screen.


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